**Problem 1 **

A beam made of a high speed **warping** machine weight 369 lbs with the warp the weight of the empty beam being 69 lbs the number of ends on the beam is 420 & the count of the yarn is 20s cotton. Find :

a) The length of the warp
b) The total length of yarn in the warp
c) Amount the warper is to be paid, if the rate of warping is 7 paisa per 1000 yds of warp.
**Solution **
Weight of warp on the beam = 369-69 = 300 lbs
**a) The length of the warp **
=(Weight of warp×count×20) ÷ (No. of ends)
=(300×20×840) ÷ 420
=12000 yds.
**b) The total length of yarn in the warp **
= Length of warp in hanks×count×No. of ends) ÷ No. of ends
= (300×20×420) ÷ 420
= 6000 hanks.
**c) Amount to be paid **= 12000 × 0.07 = 840 taka.
**Problem 2 **

A super speed beam warper with a **warping** speed of 800 yds/min is preparing a standard warp of 525 ends. If the count of the yarn is 30s & overall efficiency is 84%. Calculate the following.

I. Total length of warp produced per day of 8 hours.

II. Number of beams produced per day of 8 hours.

III. Total weight of yarn in lbs warped per day of 8 hours.

IV. Weight of yarn on a beam.

The length of warp on each beam is required to be 44352 yds. Ignore waste.

**Solution **

**I. Actual length of warp in yds/hr**= Calculated production × 60 × Efficiency

= 880 × 60 × (84÷100)

= 44352 yds

Therefore, actual production pre day of 8 hrs= 8 × 44352 = 354816 yds.

**II. No. of beams produced per day of 8 hrs in yds**

** **

= (Total length of warp produced per day of 8 hours in yds) ÷ ( Length of warp on a beam in yds)

= (354816÷44352)

= 8 beams

**III. Total weight of yarn in lbs warped pre day of 8 hrs**

=(Total length of warp produced per day of 8 hours in yds×No. of ends in the warp) ÷ (840×Count of yarn)

=(354816×525) ÷ (840×20)

= 7392 lbs.

**IV. Weight of yarn on a beam in lbs **

=(Total weight of yarns in lbs warped in 8hrs) ÷ ( No of beam produced)

=(7392÷8)

= 924 lbs

**Problem 3 **

A modern high speed beam warping machine produces 8 beams each containing 222720 yards of warp per day of 8 hrs. If the calculated warping speed of the warper is 580 yds/min. calculate its efficiency.

**Solution **

**Actual production in yds/hrs **

=(222720÷8)

= 27840 yds

**Calculated production in yds/hrs**

** **

= 580 × 60 = 34800

**Therefore, Efficiency **

= (Actual production) ÷ (Calculated production) × 100

=(27840÷34800) × 100

=80%.

### About the Editor-in-Chief:

Mazharul Islam Kiron is a textile consultant and researcher on online business promotion. He is working with one European textile machinery company as a country agent. He is also a contributor of Wikipedia.

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