Calculation of Weaving (Warping)

Problem 1 

A beam made of a high speed warping machine weight 369 lbs with the warp the weight of the empty beam being 69 lbs the number of ends on the beam is 420 & the count of the yarn is 20s cotton. Find :

a) The length of the warp
b) The total length of yarn in the warp
c) Amount the warper is to be paid, if the rate of warping is 7 paisa per 1000 yds of warp.

Solution
Weight of warp on the beam = 369-69 = 300 lbs

a) The length of the warp

=(Weight of warp×count×20) ÷ (No. of ends)

=(300×20×840) ÷ 420

=12000 yds.

b) The total length of yarn in the warp

= Length of warp in hanks×count×No. of ends) ÷ No. of ends

= (300×20×420) ÷ 420

= 6000 hanks.

c) Amount to be paid = 12000 × 0.07 = 840 taka. 

 
Problem 2
A super speed beam warper with a warping speed of 800 yds/min is preparing a standard warp of 525 ends. If the count of the yarn is 30s & overall efficiency is 84%. Calculate the following.

I. Total length of warp produced per day of 8 hours.
II. Number of beams produced per day of 8 hours.
III. Total weight of yarn in lbs warped per day of 8 hours.
IV. Weight of yarn on a beam.

The length of warp on each beam is required to be 44352 yds. Ignore waste.

Solution
I. Actual length of warp in yds/hr= Calculated production × 60 × Efficiency 

= 880 × 60 × (84÷100) 

= 44352 yds

Therefore, actual production pre day of 8 hrs= 8 × 44352 = 354816 yds.

II. No. of beams produced per day of 8 hrs in yds
 
= (Total length of warp produced per day of 8 hours in yds) ÷ ( Length of warp on a beam in yds)

= (354816÷44352) 

= 8 beams

III. Total weight of yarn in lbs warped pre day of 8 hrs 
 
=(Total length of warp produced per day of 8 hours in yds×No. of ends in the warp) ÷ (840×Count of yarn)

=(354816×525) ÷ (840×20)

= 7392 lbs.

IV. Weight of yarn on a beam in lbs

=(Total weight of yarns in lbs warped in 8hrs) ÷ ( No of beam produced)

=(7392÷8)

= 924 lbs 
 
 
Problem 3
A modern high speed beam warping machine produces 8 beams each containing 222720 yards of warp per day of 8 hrs. If the calculated warping speed of the warper is 580 yds/min. calculate its efficiency.

Solution

Actual production in yds/hrs

=(222720÷8)

= 27840 yds

Calculated production in yds/hrs
 
 = 580 × 60 = 34800

Therefore, Efficiency

= (Actual production) ÷ (Calculated production) × 100

=(27840÷34800) × 100

=80%.

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Editor-in-Chief:

Mazharul Islam Kiron is a textile consultant and researcher on online business promotion. He is working with one European textile machinery company as a country agent. He is also a contributor of Wikipedia.


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